1-cos2A/1+cos2A का मान
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Use the relation `cos(2A) = 2*cos^2A - 1 = 1 - 2*sin^2A'
`(1 - cos(2A))/(1 + cos(2A))`
=> `(1 - (1 - 2*sin^2A))/(1 + 2*cos^2A - 1)`
=> `(1 - 1 + 2*sin^2A)/(1 + 2*cos^2A - 1)`
=> `(2*sin^2A)/(2*cos^2A)`
=> `(sin^2A)/(cos^2A)`
=> `((sin A)/(cos A))^2`
=> `tan^2A`
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