[(1-cos2a+sin2a)/(1+cos2a+sin2x)]*cota
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Answered by
2
Step-by-step explanation:
1
+
cos
2
A
+
sin
2
A
1
−
cos
2
A
+
sin
2
A
Now
sin
2
A
=
2
sin
A
cos
A
and
cos
2
A
=
2
cos
2
A
−
1
=
1
−
2
sin
2
A
Hence
1
+
cos
2
A
+
sin
2
A
1
−
cos
2
A
+
sin
2
A
=
1
+
2
cos
2
A
−
1
+
2
sin
A
cos
A
1
−
(
1
−
2
sin
2
A
)
+
2
sin
A
cos
A
=
1
+
2
cos
2
A
−
1
+
2
sin
A
cos
A
1
−
1
+
2
sin
2
A
+
2
sin
A
cos
A
=
2
cos
2
A
+
2
sin
A
cos
A
2
sin
2
A
+
2
sin
A
cos
A
=
2
cos
A
(
cos
A
+
sin
A
)
2
sin
A
(
sin
A
+
cos
A
)
=
2
cos
A
2
sin
A
=
cot
A
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