Question

1-cos2A+sin2A/1+sin2A+cos2A=tanA​

Answer 1

Step-by-step explanation:

proof:

=(1-cos2A+sin2A)/(1+cos2A+sin2A)

we know that cos2A = cos^2 A - sin^2 A.

also sin2A= 2sinAcosA.

=(1-cos^2A+sin^2A +2sinAcosA)/(1+cos^2A-sin^2A+2sinAcosA)

=(2sin^2A+2sinAcosA)/(2cos^2A+2sinAcosA)

=2sinA(sinA+cosA)/2cosA(sinA+cosA)

=2sinA/2cosA

=sinA/cosA

=TanA