1-cos2A+sin2A/1+sin2A+cos2A=tanA
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Step-by-step explanation:
proof:
=(1-cos2A+sin2A)/(1+cos2A+sin2A)
we know that cos2A = cos^2 A - sin^2 A.
also sin2A= 2sinAcosA.
=(1-cos^2A+sin^2A +2sinAcosA)/(1+cos^2A-sin^2A+2sinAcosA)
=(2sin^2A+2sinAcosA)/(2cos^2A+2sinAcosA)
=2sinA(sinA+cosA)/2cosA(sinA+cosA)
=2sinA/2cosA
=sinA/cosA
=TanA
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