Question

1+cos2A/sin2A= 2cosec2A -1​

Answer 1

Answer:

Let us first find the value of left hand side (LHS) that is cos  

2

A−sin  

2

A as shown below:

       

cos  

2

A−sin  

2

A

=cos  

2

A−(1−cos  

2

A)(∵1−cos  

2

x=sin  

2

x)

=cos  

2

A−1+cos  

2

A

=2cos  

2

A−1=RHS    

 

Since LHS=RHS,

     

Hence, cos  

2

A−sin  

2

A=2cos  

2

A−1.