1-cos2a /sin2A=tan A
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1-cos2A/sin2A
=(1-cos^2 A+sin^2 A)/(2sinAcos)
=(sin^2 A+sin^2A)/2sinAcosA
=2sin^2 A/2sinAcos^2 A
=sinA/cosA
=tanA
HENCE PROVED ......
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