1/cos2Q = -1 hhgggggh
Answers
Answered by
14
tan2Q*cos2Q
= (sin2Q/cos2Q) * cos2Q
= sin2Q
= √(1-cos²2Q)
= (1-cos²2Q)12
Answered by
9
Answer:
tan2Q*cos2Q
= (sin2Q/cos2Q) * cos2Q
= sin2Q
= √(1-cos²2Q)
= (1-cos²2Q)12
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