Question

(1+cos²x)=sec²d then prove sin d+sin²d=1​

Answer 1

step by step illustration:

1 +cos²d= sec²d

1=sec²d-cos²d

now, lets centralise our focus upon

sind + sin²d =1

therefore, (1-cos²d)^1/2 + 1-cos²d=1

so, cos²d = (1-cos²d)^1/2

hence cos⁴d= 1-cos²d

so, cos⁴d+ cos²d =1 and this is what we have to basically prove......

now, lets come back to sec²d-cos²d=1

so, here 1/cos²d -cos²d =1

thats because sec²d=1/cos²d

now, 1-cos⁴d=cos²d

so, from here we got , cos²d +cos⁴d=1

hence, we got the result........

so, sind +sin²d=1

hope it helps......

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