1/cos80° - sqrt3/sin80°
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Now,
1/cos80° - √3/sin80°
= (sin80° - √3 cos80°)/(sin80° cos80°)
= 4 (1/2 sin80° - √3/2 cos80°)/(2 sin80° cos80°)
= 4 (sin80° cos60° - cos80° sin60°)/(sin160°)
= 4 sin(80° - 60°) / sin(180° - 20°)
= 4 sin20° / sin20°
= 4
Rules used :
sin(A - B) = sinA cosB - cosA sinB
sin(180° - A) = sinA
sin60° = √3/2
cos60° = 1/2
2 sinA cosA = sin2A
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