Math, asked by purohitviahal72, 1 year ago

1/cos80° - sqrt3/sin80°

Answers

Answered by MarkAsBrainliest
20
\bold{Answer :}

Now,

1/cos80° - √3/sin80°

= (sin80° - √3 cos80°)/(sin80° cos80°)

= 4 (1/2 sin80° - √3/2 cos80°)/(2 sin80° cos80°)

= 4 (sin80° cos60° - cos80° sin60°)/(sin160°)

= 4 sin(80° - 60°) / sin(180° - 20°)

= 4 sin20° / sin20°

= 4

Rules used :

sin(A - B) = sinA cosB - cosA sinB

sin(180° - A) = sinA

sin60° = √3/2

cos60° = 1/2

2 sinA cosA = sin2A

#\bold{MarkAsBrainliest}
Answered by AryanTennyson
7
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