Question

(1-cosA) (1+cosA) =? 1️⃣cos^2A , 2️⃣sin^2A, 3️⃣tan^2A,4️⃣sec^2A
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Answer 1

Answer:

[1-cosA][1+cosA]

= $1^{2}$ - $cosA^{2}$  [ using identity: $a^{2} - b^{2} = [a-b]*[a+b]$

therefore, using Trigonometric identity

it is $sinA^{2}$

Therefore Answer: 2)

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