1+cosA÷1-cosA + 1-cosA÷1+cosA =?
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Answer:
(1+cosA)/(1-cosA) + (1-cosA)/(1+cosA)
= (1+cosA)²/(1-cos²A) + (1-cosA)²/(1-cos²A)
= (1 + 2cosA + cos²A + 1 - 2cosA + cos²A)/sin²A
=2cosec²A + 2tan²A
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