Question

√1-cosa*/1+cosa+√1+cosa/1-cosa=2coseca

Answer 1

Answer:

√[(1-cosA)²/(1-cos²A)] + √[(1+cosA)²/(1-cos²A)],

√[(1-cosA)²/sin²A] + √[(1+cosA)²/(sin²A)],

(1-cosA)/sinA + (1+cosA)/sinA,

(1-cosA+1+cosA)/sinA,

2/sinA,

2cosecA

hope ut helps♥♡♥♡♥♡♥♡

Answer 2

2cose 2 if u need explanation so tell me