1+cosA /1-cosA = (cosecA + cotA)2
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Step-by-step explanation:
1+cos A/1-cos A= (cosecA+cotA)2
1+cosA/1-cosA ×1+cosA/1+cosA
(1+cosA)2/(1-cosA)(1+cosA)
(1+cos A)/sin2A
TAKING RHS:-
(1/1/sinA) +(cosA /sinA)
(1+cosA)2/sin2A=LHS
Hence proved
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