√1+cosA /√1-cosA =cosecA +cotA
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Step-by-step explanation:
Side AB and BC and median AD of a triangle ABC are respectively proportional to side------
No figure given
1−cosA
1+cosA
×
1+cosA
1+cosA
=
1−cos
2
A
(1+cosA)
2
=
sin
2
A
1+cosA
=
sinA
1+cosA
⇒cscA+cotA
Answered by
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Answer:
answer is in attachment
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