Question

√1- cosA/ √1+ cosA = cosecA - cotA. prove​

Answer 1

To prove- √(1+cosA)/√(1-cosA)=cosecA + cot A

Proof-

LHS-

√(1+cosA)/√(1-cosA)

Multiplying with √(1+cosA) on both numerator and denominator, we have,

={√(1+cosA)*√(1+cosA)}/{√(1-cosA)*√(1+cosA)}

=[√{(1+cosA)*(1+cosA)}]/[√{(1-cosA)*(1+cosA)}]

={√(1+cosA)²}/{√(1²-cos²A)}

=(1+cosA)/√(sin²A)

=(1+cosA)/sinA

=(1/sinA)+(cosA/sinA)

=cosecA + cotA

Hence proved…

Answer 2

Step-by-step explanation:

(a-b)^2=(a-b)(a-b)

(a^2-b^2)(a-b)(a+b)

sin^2A=1-cos^2A