Question

1-cosA/1+cosA=(CosecA-cotA)
${?}^{2}$
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Answer 1

Answer:

Simplifying LHS

Simplifying LHS1-cosA/1+cosA

(1-cosA)/(1+cosA)*(1-cosA)/(1-cosA)

(1-cosA) ^2/1-cos^2A

(1-cosA) ^2/sin^2A

[1-cosA/sinA]^2

[1/sinA - cosA/sinA]^2

[cosecA-cotA]^2

HENCE PROVED

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Answer 2

Answer:

Please see the answer

OK