Question

√1-cosA/1-cosA=sinA/1+cosA

Answer 1

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Answer 2

》》solution《《

LHS = [(√1-cosA)/(√1+cosA)

Multiply numerator and denominator by [(√1+cosA)/(√1+cosA)

we get

= [√(1-cosA)(1+cosA)]/(√1+cosA)²

= √(1-cos²A)/(1+cosA)

= (√sinA)²/(1+cosA)

= sinA/(1+cosA)=RHS

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