Question

(1-cosA)(1+secA)=sinA tanA

Answer 1

Step-by-step explanation:

(1 - cosA) . (1 + 1/cosA)

(1 - cos A) {(cosA + 1)/cosA}

{we know that : (a+b)×(a-b) = a^2 - b^2}

1 - cos^2A/cosA

sin^2/cosA

sinA . sinA/cosA

sinA.tanA