Question

(1-cosA)(1+secA) =tan A sinA prove​

Answer 1

Answer:

(1-cosA) (1+secA)

1-cosA+secA-cosA secA

1-cosA+1/cosA-1

(1-cosA+1/cosA

(1-cos2A) /cosA

sin2A/cosA

sinA*sinA/cosA

sinA*tanA

Answer 2

Answer:

Step-by-step explanation: (1-cos A ) ( 1+ 1/cos A )

(1-cos A ) ( cos A +1 / cos A )

[(1- cos A )(cos A +1) ] / cos A

Sin^2 A / cos A

Sin A /cos A . Sin A

tan A . Sin A

Therefore RHS = LHS