Question

(1+cosA/8)(1+cos3A/8)(1+cos5A)(1+cos7A/8)=1/8
$(1 + \frac{ \cos( \alpha ) }{8} )(1 + \frac{ \cos(3 \alpha ) }{8} )(1 + \frac{ \cos(5 \alpha ) }{8} )(1 + \frac{ \cos(7 \alpha ) }{8} ) = \frac{1}{8}$
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Answer 1

Capture.png is the aws open it to see