1+cosA/sin^2 =sinA/1-cosA
Anonymous:
is this (1+cos A)/sin^2 A
or 1 + (cos A/ sin^2 A) ??
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1+cosA /sin² =sinA/1-cosA
LHS = (1+cos A /sin ²) ( 1 - cos A / 1 - cos A )
= (1+cos A)( 1 - cos A)/ (sin ²) (1 - cos A)
=( 1² - cos ² A ) / (sin ² A) (1 - cos A)
= sin ² A / (sin ²) (1 - cos A)
= 1 / (1 - cos A)
LHS = (1+cos A /sin ²) ( 1 - cos A / 1 - cos A )
= (1+cos A)( 1 - cos A)/ (sin ²) (1 - cos A)
=( 1² - cos ² A ) / (sin ² A) (1 - cos A)
= sin ² A / (sin ²) (1 - cos A)
= 1 / (1 - cos A)
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