Question

1+cosA/sin^2A=1/1-cosA​

Answer 1

Here is the answer .
Hope it helps !! :)

Answer 2

LHS =

$\frac{1 + \cos\: a}{ { \sin }^{2} \: a } \\ \frac{1 + \cos \: a \: }{1 - \cos {}^{2} a} \\ \frac{1 + cos \: a}{(1 + cos \: a) \times (1 - cos \: a)} \\ \frac{1}{1 - cos \: a}$

So, LHS = RHS, Hence proved