Math, asked by sh2i0aulolotimalmahi, 1 year ago

1+cosA-sin2A/sinA1+cosA=cot2A

Answers

Answered by ARoy

1

(1+cosA-sin²A)/sinA(1+cosA)
={1+cosA-(1-cos²A)}/sinA(1+cosA)
=(1+cosA-1+cos²A)/sinA(1+cosA)
=cosA(1+cosA)/sinA(1+cosA)
=cosA/sinA
=cotA
∴, LHS≠RHS

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