1+cosA-sinA/1+cosA+sinA=1+sinA/cosA
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Answer:
Step-by-step explanation:
taking L.H.S.
(1+cosA-sinA)/(1+cosA+sinA)
Rationalization numinator and denominator
=> [(1+cosA)-sinA]^2/(1+cosA)^2-(sinA)^2
=> (1+cos^2A+2cosA+sin^2A-2sinA-2sinAcosA)/(1+cos^2A+cosA-sin^2A)
=> 2(1+cosA-sinA-sinAcosA) /2cosA(cosA-1)
=> 1+sinA/cosA
LHS=RHS
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