Question

1+cosa+sina/1+cosa-sina=1+sina/cosa​

Answer 1

Answer:

proof:

LHS=

1+cos A+ sin A/1+cos A-sin A

• DIVIDING NUMERATOR AND DENOMINATOR BY cos A, we get,

sec A+tan A+ 1/sec A-tan A+1

sec A+tan A+ (sec^2 A - tan^2 A)/sec A-tan A+1     (since, sec^2 A - tan^2 A=1)

(sec A+tan A)+(sec A +tan A)(sec A - tan A)/sec A-tan A+1

(sec A+tan A)(1+sec A - tan A)/(sec A-tan A+1)

sec A+tan A = 1/cos A+sin A/cos A

=1+sin A/cos A

hence proved

Step-by-step explanation: