Question

1+cosA+sinA/1+cosA-sinA= 1+sinA/cosA

Answer 1

am I to prove that? pls explain

Answer 2

Hey mate, here is your answer,

LHS =

1+cosA+sinA/1+cosA-sinA

Dividing each part of fraction; namely numerator and denominator by cosA, we get

=secA +1+tanA/secA+1-tanA

=secA+tanA+1/secA-tanA+(sec²A-tan²A)

=secA+tanA+1/(secA-tanA)(secA+tanA+1)

=1/secA-tanA

=secA+tanA. (On multiplying secA+tanA to num. and denom.)

= 1/cosA + sinA/cosA

= (1+sinA)/cosA

= RHS

Hence, Proved.

hope it helps....