Math, asked by kurosaki006, 10 days ago

1+cosA+sinA/1+cosA-sinA = secA+tanA

Answers

Answered by MAHENDRASSMM3219

0

Step-by-step explanation:

sin^2A + cos^2A = 1 tanA = sinA/cosA cotA = cosA/sinA 1 + cot^2A = cosec^2A tan^2A + 1 = sec^2A cosecA = 1/sinA secA = 1/cosA cotA = 1/tanA

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