Question

(1+cosA/sinA)^2=1+cosA/1-cosA

Answer 1

LHS=(1+cosA/sinA)^2
(1+cosA)^2/sinA^2
(1+cosA)(1+cosA)/1-cos^2
#((as sinA^2=1-cos^2A))
(1+cosA)(1+cosA)/(1-cosA)(1+cosA)
(1+cosA)/(1-cosA)
LHS=RHS
HENCE,PROVED


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Answer 2

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