1+cosA/sinA=sinA/1-cosA
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LHS:
1+ cosA/sinA
RHS:
SinA/1-cosA
Multiplying and divided by 1+cosA in numerator and denominator.
SinA/1-cosA × 1+cosA/1+cosA
SinA(1+cosA)/1-cos^2A
As we know 1-cos^2A=sin^2A putting value we get
SinA(1+cosA)/sin^2A
Cancelling sinA in numerator and denominator we get
1+cosA/sinA = LHS
LHS=RHS
Hence proved
1+ cosA/sinA
RHS:
SinA/1-cosA
Multiplying and divided by 1+cosA in numerator and denominator.
SinA/1-cosA × 1+cosA/1+cosA
SinA(1+cosA)/1-cos^2A
As we know 1-cos^2A=sin^2A putting value we get
SinA(1+cosA)/sin^2A
Cancelling sinA in numerator and denominator we get
1+cosA/sinA = LHS
LHS=RHS
Hence proved
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