Math, asked by jerrin25, 11 months ago

1+cosA/sinA=sinA/1-cosA​

Answers

Answered by NightFury
1
LHS:

1+ cosA/sinA


RHS:

SinA/1-cosA

Multiplying and divided by 1+cosA in numerator and denominator.

SinA/1-cosA × 1+cosA/1+cosA

SinA(1+cosA)/1-cos^2A

As we know 1-cos^2A=sin^2A putting value we get

SinA(1+cosA)/sin^2A

Cancelling sinA in numerator and denominator we get

1+cosA/sinA = LHS

LHS=RHS

Hence proved
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