Math, asked by sanaypise, 8 months ago

1+cosA/sinA = sinA/1-cosA​

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Answered by junali007
1

Answer:

= \frac{ 1 + cosA }{ sinA } \\ \\ = \frac{ sinA(1 + cosA ) }{ { \sin}^{2}A } \\ \\ = \frac{(1 + cosA) sinA }{ {(1 - cosA )}^{2} } \\ \\ = \frac{(1 + cosA) sinA }{(1 + cosA)(1 - cos A) } \\ \\ = \frac{ sinA}{ cosA}

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