Question

1-CosA/SinA=SinA/1+CosA ​

Answer 1

Answer:

fbfjfbffhnhgdhfhfbfhhththfhf

Answer 2

$\tt{{\huge{{\underline{Question}}}}}$

Prove :- $\sf{{\dfrac{1-cos~A}{sin~A}}={\dfrac{sin~A}{1+cos~A}}}$

$\tt{{\huge{\underline{Answer}}}}$

$\sf{{\dfrac{1-cos~(A)}{sin~(A)}}={\dfrac{sin~(A)}{1+cos~(A)}}}$

${\bold{\boxed{\sf {\footnotesize{Manipulating ~left~side~{\dfrac{1-cos~(A)}{sin~(A)}}}}}}}$

Rewrite using trigonometric identity

$\sf{={\dfrac{sin~(A)}{1+cos~(A)}}}$

We showed that two sides could take the same form

⇒True