Question

1+cosea/sina=sina/1-cose​

Answer 1

Answer:

1+cos A

sin A

on multiply both numinator and denominator by sinA

(1+cosA) × sinA

sinA sin A

(1+cosA) sin A ⇒ (1+cosA)sinA as use sin²A+cos²A=1

Sin²A (1-cos²A)

(1+cosA) sinA as use a²-b²=(a+b)(a-b)

(1+cosA)(1-cosA)

sinA = RHS

(1-cosA)

Hence Proved

Answer 2

here u go lhs = Rhs bingooo