Question

1/cosec^2 theta +1/sec^2 theta=

Answer 1

Answer:

1/cosec^2 theta +1/sec^2 theta= 1

Step-by-step explanation:

1/cosec²Q + 1/sec²Q

since sinQ= 1/cosecQ and cosQ=1/secQ

so

sin²Q + cos²Q

and

sin²Q + cos²Q=1