1/ cosec^2theta+ 1/sec^ 2theta =1
Answers
(sec 2
(sec 2 θ−1)(1−csc 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2 θ=−cot 2 θ)( as cot 2
(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2 θ=−cot 2 θ)( as cot 2 θ= tan 2 θ1 )
Answer:
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