Question

1/ cosec^2theta+ 1/sec^ 2theta =1​

Answer 1

(sec 2

(sec 2 θ−1)(1−csc 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2 θ=−cot 2 θ)( as cot 2

(sec 2 θ−1)(1−csc 2 θ)=(tan 2 θ)(−cot 2 θ)=−1( as sec 2 θ−tan 2 θ=1⇒sec θ −1=tan 2 θ)(as csc 2 θ−cot 2 θ=1⇒1−csc 2 θ=−cot 2 θ)( as cot 2 θ= tan 2 θ1 )

Answer 2

Answer:

Hope it help uh dear!! ☺✌