Question

1 + (cosec x tan y)^2÷1 + (cosec z tan y)^2​

Answer 1

Answer:

Given , sec

−1

1+x

2

+cosec

−1

(

y

1+y

2

)+cot

−1

(

z

1

)=π

⇒tan

−1

x+tan

−1

y+tan

−1

z=π

⇒tan

−1

(

1−xy−yz−zx

x+y+z−xyz

)=π=tan

−1

(0)

⇒x+y+z−xyz=0

⇒x+y+z=xyz