Math, asked by pritamponnada, 8 months ago

1-cosec50 cosec 35 cosec 5+(cos100+sin20+ cos 10÷sin50 sin 35 sin 5)​

Answers

Answered by topwriters
1

1-cosec50 cosec 35 cosec 5+(cos100+sin20+ cos 10÷sin50. sin 35. sin 5)​ = -55.22

Step-by-step explanation:

1-cosec50 cosec 35 cosec 5+(cos100+sin20+ cos 10÷sin50. sin 35. sin 5)​

 = 1 - 1/sin 50. 1/sin35. 1/sin 5 + (Cos 100 + Sin 20 + Cos 10 / Sin 50. Sin 35. Sin 5)

= 1 - (1/0.7660. 1/0.5736. 1/0.0872) + (-0.1736 +  0.3420 + 0.9848 / 0.7660 * 0.5736* 0.0872)

= 1 - (1/ 0.0383) + (1.1532 / 0.0383)

= 1 - (2.1532 / 0.0383)

= 1 - 56.22

= -55.22

Similar questions