Question

1+cosecA/cosecA = cos2A/ 1-sinA

Answer 1

sol=LHS Multiply above and below bysinA.

=(1-sinA)/(1+sinA) , Again multiply above and below by (1+sinA).

=(1-sin^2A)/(1+sinA)^2

=cos^2A/(1+sinA)^2

=[cosA/(1+sinA)]^2 , proved

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