Math, asked by Mush7189, 11 months ago

1/cosecA-cotA=1/sinA-1/cosecA+cotA

Answers

Answered by sprao534
1

Please see the attachment

Attachments:
Answered by ankurbadani84
2

Answer:

Step-by-step explanation:

Missing point in question

1/cosecA-cotA - 1/sin A = 1/sinA - 1/cosecA+cotA

Answer :-

1/cosecA-cotA - 1/sin A = 1/sinA - 1/cosecA+cotA

1/cosecA-cotA + 1/cosecA+cotA = 2/sin A

Now consider LHS

1/cosec A-cot A + 1/cosec A+cot A

= (cosec A + cot A + cosec A - cot A) / (cosec A-cot A) (cosec A+cot A)

= 2 cosec A / (cosec ² A - cot ²A)

Now, cosec ² A - cot ²A = 1

= 2 cosec A

= 2/sin A

= RHS

Hence Proved.

Similar questions