Math, asked by Sumant6612, 1 year ago

1/cosecA-cotA - 1/sinA = 1/sinA - 1/cosecA+cotA


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Answers

Answered by Anonymous
6
bhai itna mushkil Qs aayenge toh bhut muskil hog xam mei lekin bn gaya lastly 1/cosecA-cotA - 1/sinA= 1/sinA - 1/cosecA+cotA Taking LHS 1/(cosecA-cotA )- 1/sinA 1/(cosecA-cotA ) *(cosecA+cotA )/(cosecA +cotA )- 1/sinA (rationalizing the denominator) (cosecA +cotA )/(cosec^2A +cot^2A )-1/sinA As (cosec^2A +cot^2A )=1 (cosecA +cotA ) - 1/sinA 1/sinA +(cotA-cosecA) 1/sinA +(cotA-cosecA)*(cosecA+cotA )/(cosecA+cotA ) (ratioalizing the numerator) 1/sinA +(cot^2A-cosec^2A)/(cosecA+cotA ) 1/sinA +1/(cosecA+cotA ) As (cosec^2A +cot^2A )=1 =RHS
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Sumant6612: thankx
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