Question

1/cosecA -cotA -1/sinA = 1/sinA - 1/cosecA +cotA

Answer 1

Answer:

Answer

xcos

3

y+3xcosysin

2

y=14 ...(1)

xsin

3

y+3xcos

2

ysiny=13 ...(2)

Adding (1) and (2)

x(cosy+siny)

3

=27

Subtracting (2) from (1)

x(cosy−siny)

3

=1

cosy−siny

cosy+siny

=

1

3

Divide numerator and denominator by cosy

⇒tany=

2

1

⇒siny=±

5

1

⇒cosy=±

5

2

....{Take a triangle with tany=

2

1

find other sides of the triangle we get siny and cosy}

∴sin

2

y+2cos

2

y=(±

5

1

)

2

+2(±

5

2

)

2

=

5

9

Answer 2

1/cosecA-cotA -1/sina

=cosecA+cotA-cosecA

=cosecA-(cosecA-cotA)

=1/sinA-1/cosecA+cotA