Question

(1+cosectetha - cot tetha)/(1+cosectetha +cottetha)
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Answer 1

Answer:

Let. theta=x

(cosecx-cotx)=1/(cosecx-cotx)

or. (cosecx-cotx)^2=1

or. cosec^2(x)+cot^2(x)-2cosecx.cotC=1

or. cosec^2(x)-1+cot^2(x)-2cosec(x).cot(x)=0

or. cot^2(x)+cot^2(x)-2.cosec(x).cot(x)=0

or. 2.cot^2(x)-2.cosec(x).cot(x)=0

or. 2.cot(x){cot(x)-cosec(x)}=0

Either. cot x=0

cot x= cot π/2

or. x=π/2. Answer.

Or. cotx-cosecx=0

or cotx=cosecx

or. cosx/sinx=1/sinx

or. cosx=1

or. cosx=coso°

or. x=0° Answer

I hope this helps