Question

√1+coso/1-coso=coseco+coto​

Answer 1

Step-by-step explanation:

√1+coso/1-coso=coseco+coto

LHS = √1+coso / √1-coso

rationalising the denominator, we get

= √1+coso x √1+coso / √1-coso x √1+coso

= ( √1+coso )^2 / √ 1 - cos^2 (o)

= ( √1+coso )^2 / √ sin^2 (o)

= 1 + cos o / sin (o)

= 1 / sin o + cos o / sin o

= cosec o + cot o = RHS