Question

√1+CosQ/1-CosQ= Cosec Q +CotQ​

Answer 1

$\bf\large\underline\pink{Solution:-}$

Hi ,

LHS = sqrt [ ( 1 + cos A ) / ( 1 - cos A )

Multiply numerator and denominator with ( 1 + cos A )

= sqrt [ ( 1 + cos A ) ( 1 + cos A ) / ( 1 - cos A ) ( 1 + cos A ) ]

= sqrt [ ( 1 + cos A ) ^2 / ( 1^2 - cos ^2 A ) ]

[ since ( a + b ) ( a - b ) = a^2 - b ^2 ]

= sqrt [ ( 1 + cos A ) ^2 / ( sin ^2 A ) ]

= ( 1 + cos A ) / sin A

= ( 1 / sin A ) + ( cos A / sin A )

= cosec A + cot A

= RHS

I hope this helps you.

****

$\bf\huge\underline\red{Follow me}$

Answer 2

.......hope this attachment will help you.......