Question

1+ cosQ/sin^2Q=1/1-cosQ
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Answer 1

$\frac{1+CosQ}{Sin²Q}$

$\frac{1+CosQ}{1-Cos²Q}$

$\frac{1+CosQ}{(1+CosQ)(1-CosQ)}$

$\frac{1}{1-CosQ}$

I wish it will be helpful for u

Answer 2

Step-by-step explanation:

$\frac{1+CosQ}{Sin²Q}</p><p>\frac{1+CosQ}{1-Cos²Q}</p><p>\frac{1+CosQ}{(1+CosQ)(1-CosQ)}</p><p>\frac{1}{1-CosQ}$