Math, asked by gautamisane, 10 months ago

1 - cosx / sinx + sinx / 1 - cosx​

Answers

Answered by Anonymous
1

 \frac{1 - cosx}{sinx }  +  \frac{sinx}{1 - cosx}

 \frac{ {(1 - cosx)}^{2} + sin {x}^{2}  } {(sinx)(1 - cosx)}

\frac{2 - 2cox}{(sinx)(1 - cosx)}

 \frac{2(1 - cosx)}{(sinx)(1 - cosx)}

 \frac{2}{sinx}

2cosecx

Thanks.

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