1+cosx÷sinx=sinx÷1 -cosx
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sin^2x = (1 - cosx)(1 + cosx)
=> sin^2x = 1 - cos^2x
=> sin^2x + cos^2x = 1
=> 1 = 1
=> sin^2x = 1 - cos^2x
=> sin^2x + cos^2x = 1
=> 1 = 1
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multiplying & dividing LHS by 1-cosx
i.e 1+cosx(1-cosx)/sinx(1-cosx)=1-cos^2x/sinx(1-cosx)=sin^2x/sinx(1-cosx)= sinx / 1-cosx
I think it might help you
i.e 1+cosx(1-cosx)/sinx(1-cosx)=1-cos^2x/sinx(1-cosx)=sin^2x/sinx(1-cosx)= sinx / 1-cosx
I think it might help you
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