Question

(1 + cot 0 - cosec )(1 + tan 8 + sec 6) = 2​

Answer 1

Answer:

Step-by-step explanation:

(1+ cot A - cosec A)(1+tanA+secA)=2 \\ 
L.H.S. \\ 
=(1+cotA-cosecA)(1+tanA+secA) \\
= (1 +  \frac{cosA}{sinA} - \frac{1}{sinA} )(1+ \frac{sinA}{cosA} + \frac{1}{cosA} ) \\
= ( \frac{sinA+cosA-1}{sinA} )( \frac{cosA+sinA+1}{cosA} ) \\
=  \frac{ (sinA+cosA)^{2}- 1^{2}  }{sinA.cosA}  \\
=  \frac{ sin^{2}A + cos^{2}A + 2sinA.cosA-1 }{sinA.cosA}  \\ 
=  \frac{ 1 + 2sinA.cosA-1 }{sinA.cosA}  \\ 
=  \frac{2sinA.cosA }{sinA.cosA}  = 2 = R.H.S.

Hence, proved

Answer 2

Answer:

YES.. ANS IS RIGHT.......