Question

(1/cot^ 2 theta) -1=?​

Answer 1

Step-by-step explanation:

(1/ cos^2A/sin^2A) - 1

(sin^2A/cos^2A) - 1

(sin^2A - cos^2A/ cos^2A)

1-cos^2A-cos^2A/cos^2A

1-2cos^2A/cos^2A

OR

Through changing cos^2A

sin^2A - cos^2A / cos^2A

sin^2A - 1-sin^2A/ cos^2A

-1/cos^2A

= -sec^A

OR

1-2cos^2A / cos^2A

Can also be written as

sec^2A- 2