Question

1+ (cot^2 theta /1+ cosec theta) =????
​

Answer 1

Step-by-step explanation:

LHS =1+

(1+cosecα)

cot

2

α

=1+

(1+cosecα)

(cosec

2

α−1)

[∵cot

2

α=cosec

2

α−1]

=1+

(cosecα+1)

(cosecα−1)(cosecα+1)

[∵a

2

−n

2

=(a−b)(a+b)]

=cosecα