1+cot^2 thita×sin^2 thita is equal to 1
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Solution : 1+cot^2theta×sin^2theta=1
LHS=(1+cot^2theta)sin^2theta
=sin^2theta+(sin^2theta×cot^2theta)
=sin^2theta+{sin^2theta×(cos^2theta÷sin^2theta)}
=sin^2theta+cos^2theta
=1=RHS
Proved.
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