Math, asked by Ayushsinghofficial, 1 year ago

(1+cot^2theta)sin^2=1

Answers

Answered by saxenavs
0
may be dear it will be helpful for u...

(1+cos^2thetha/sin^2thetha)sin^2thetha
{(sin^2thetha+cos^2thetha)/sin^2thetha}/sine^2thetha
=1
Answered by MOSFET01
0

(1 +  \cot ^{2} x ) \sin ^{2} (x) = 1 \\ ( \sin ^{2} (x)  +  \frac{ \cos ^{2} (x) }{ \sin ^{2} (x) }  \times  \sin^{2} x   = 1 \\  \sin^{2}x + cos {}^{2} x = 1
solution as per your requirement
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